JPA Hibernate 方法字段名查询,常用查询,JPA Hibernate关键词

Sun 1年前 ⋅ 7665 阅读

根据方法名,对应字段名生成SQL语句

@Repository
public interface UserRepository extends JpaRepository<User,Long>, JpaSpecificationExecutor<User> {
//方法名直接映射查询条件
User findByUsername(String username);
User findByEmail(String email);
//方法名映射加Hql
@Query("FROM User where userType=:UserType")
List<User> findByUserTypeIn(@Param("UserType")Integer UserType);
}

SQL联想关键字对应实体详细介绍

关键词 Demo JPQL 语句片段
And findByLastnameAndFirstname … where x.lastname = ?1 and x.firstname = ?2
Or findByLastnameOrFirstname … where x.lastname = ?1 or x.firstname = ?2
Is,Equals findByFirstname,
findByFirstnameIs,
findByFirstnameEquals
… where x.firstname = ?1
Between findByStartDateBetween … where x.startDate between ?1 and ?2
LessThan findByAgeLessThan … where x.age < ?1
LessThanEqual findByAgeLessThanEqual … where x.age ⇐ ?1
GreaterThan findByAgeGreaterThan … where x.age > ?1
GreaterThanEqual findByAgeGreaterThanEqual … where x.age >= ?1
After findByStartDateAfter … where x.startDate > ?1
Before findByStartDateBefore … where x.startDate < ?1
IsNull findByAgeIsNull … where x.age is null
IsNotNull,NotNull findByAge(Is)NotNull … where x.age not null
Like findByFirstnameLike … where x.firstname like ?1
NotLike findByFirstnameNotLike … where x.firstname not like ?1
StartingWith findByFirstnameStartingWith … where x.firstname like ?1 (parameter bound with appended %)
EndingWith findByFirstnameEndingWith … where x.firstname like ?1 (parameter bound with prepended %)
Containing findByFirstnameContaining … where x.firstname like ?1 (parameter bound wrapped in %)
OrderBy findByAgeOrderByLastnameDesc … where x.age = ?1 order by x.lastname desc
Not findByLastnameNot … where x.lastname <> ?1
In findByAgeIn(Collection<Age> ages) … where x.age in ?1
NotIn findByAgeNotIn(Collection<Age> age) … where x.age not in ?1
True findByActiveTrue() … where x.active = true
False findByActiveFalse() … where x.active = false
IgnoreCase findByFirstnameIgnoreCase … where UPPER(x.firstame) = UPPER(?1)

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